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n^2-7n-14=0
a = 1; b = -7; c = -14;
Δ = b2-4ac
Δ = -72-4·1·(-14)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{105}}{2*1}=\frac{7-\sqrt{105}}{2} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{105}}{2*1}=\frac{7+\sqrt{105}}{2} $
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